Answer
Please see the work below.
Work Step by Step
We know that
$Q_{water}=Q_{fusion}$
$\implies m_{water} c\Delta T=m_{ice}L_f$
We plug in the known values to obtain:
$(16)(4184)(25)=m_{ice}(334000)$
$m_{ice}=5.0Kg$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 17 - Exercises and Problems - Page 314: 52
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