Answer
$T = 2220~K$
Work Step by Step
We can find the temperature:
$\frac{3}{2}~k~T = \overline{KE}$
$T = \frac{2~\overline{KE}}{3~k}$
$T = \frac{(2)(4.60\times 10^{-20}~J)}{(3)(1.38\times 10^{-23}~J/K)}$
$T = 2220~K$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 13 - Problems - Page 499: 76
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