College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 13 - Problems - Page 499: 59

Answer

The SI units of $PV$ are joules.

Work Step by Step

Pressure is measured in units of $N~m^{-2}$ which can be expressed as $kg~m^{-1}~s^{-2}$ Volume is measured in units of $m^3$ We can find the units of $PV$: $(kg~m^{-1}~s^{-2})(m^3) = kg~m^2~s^{-2} = joules$ The SI units of $PV$ are joules.
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