Answer
$T = 1546~K$
Work Step by Step
We can find the temperature:
$\frac{3}{2}~k~T = \overline{KE}$
$T = \frac{2~\overline{KE}}{3~k}$
$T = \frac{(2)(3.20\times 10^{-20}~J)}{(3)(1.38\times 10^{-23}~J/K)}$
$T = 1546~K$
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