Answer
The gas occupies a volume of $0.0224~m^3$
Work Step by Step
We can find the volume:
$PV = NkT$
$V = \frac{NkT}{P}$
$V = \frac{(6.022\times 10^{23})(1.38\times 10^{-23}~J/K)(273~K)}{1.013\times 10^5~Pa}$
$V = 0.0224~m^3$
The gas occupies a volume of $0.0224~m^3$
