Answer
37.5% of Carbon.
Work Step by Step
The represented molecule is Methanol ($C_{}H_{3}O_{}H_{}$)
1. Find the mass of $C_{}H_{3}O_{}H_{}$:
C: 12 x 1 = 12
H: 1 x 4 = 4
O: 16 x 1 = 16
16 + 4 + 12 = 32
2. Divide the mass of Carbon in the molecule by the total mass:
$\frac{12}{32}$ = 0.375
3. Multiply the result by 100%:
0.375 x 100% = 37.5%
