Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 114: 3.28a

Answer

About 27.27% of Carbon.

Work Step by Step

The represented molecule is $C_{}O_{2}$. 1. Find the mass of $C_{}O_{2}$: C: 12 x 1 = 12 O: 16 x 2 = 32 12 + 32 = 44 2. Divide the mass of Carbon in the molecule by the total mass: $\frac{12}{44}$ $\approx$ 0.2727 3. Multiply the result by 100%: 0.2727 x 100% = 27.27%
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