Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 114: 3.25a

Answer

16.84%

Work Step by Step

The percentage of oxygen in the substance is determined by the following equation: $\%O = \frac{(number -of -oxygen- atoms)\times(atomic- mass- of- oxygen)}{molecular- mass -of- morphine}\times100\%$ So, molecular mass of morphine is: MM(Morphine)= $(17\times12)+(19\times1)+(14\times1)+(3\times16)=285amu$ Therefore, $\%O=\frac{(3\times16)}{285}\times100\% =16,84\%$
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