Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 114: 3.27c

Answer

Approximately 64.62% of Carbon.

Work Step by Step

1. Find the mass of $C_{7}H_{14}O_{2}$: C: 12 x 7 = 84 H: 1 x 14 = 14 O: 16 x 2 = 32 84 + 14 + 32 = 130 2. Divide the mass of Carbon by the total mass of the molecule: $\frac{84}{130}$ $\approx$ 0.6462. 3. Multiply the result by 100%: 0.6462 x 100% = 64.62%
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