Answer
$C_5H_6O(l)+6O_2(g)\rightarrow 5CO_2(g)+3H_2O(g)$
This is combustion.
Work Step by Step
$C_5H_6O(l)+O_2(g)\rightarrow CO_2(g)+H_2O(g)$
This is a combustion reaction because a hydrocarbon is reacting with oxygen to create carbon dioxide and water.
Add a coefficient of 5 to $CO_2$ to balance $C$.
Add a coefficient of 3 to $H_2O$ to balance $H$.
$C_5H_6O(l)+O_2(g)\rightarrow 5CO_2(g)+3H_2O(g)$
Add a coefficient of 6 to $O_2$ to balance $O$.
$C_5H_6O(l)+6O_2(g)\rightarrow 5CO_2(g)+3H_2O(g)$
