Answer
$$1.08*10^{21} molecules$$
Work Step by Step
We use conversions to find:
$$ \frac{.324 g}{1}* \frac{1 mol}{180.15 g}* \frac{6.022*10^{23} molecules}{mol}\\ =1.08*10^{21} molecules$$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 2 - Chemical Compounds - Questions for Review and Thought - Topical Questions - Page 90d: 85b
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