Answer
$5.93\times10^{21}\,Au\,atoms$
Work Step by Step
$1.94\,g\,Au=$
$1.94\,g\,Au\times\frac{1\,mol\,Au}{197\,g\,Au}\times\frac{6.022\times10^{23}\,Au\,atoms}{1\,mol\,Au}$
$=5.93\times10^{21}\,Au\,atoms$
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