Answer
$1.80\times10^{-3}\,mol\text{ aspirin}$
$2.266\times10^{-2}\,mol\,NaHCO_{3}$
$5\times10^{-3}\,mol\text{ citric acid}$
Work Step by Step
Amount of aspirin=
$324\times10^{-3}\,g\text{ aspirin}\times\frac{1\,mol\,\text{aspirin}}{180.158\,g\text{ aspirin}}$
$=1.80\times10^{-3}\,mol\text{ aspirin}$
Amount of $NaHCO_{3}$=
$1904\times10^{-3}\,g\,NaHCO_{3}\times\frac{1\,mol\,NaHCO_{3}}{84.007\,g\,NaHCO_{3}}$
$=2.266\times10^{-2}\,mol\,NaHCO_{3}$
Amount of citric acid=
$1000\times10^{-3}\,g\text{ citric acid}\times\frac{1\,mol\,\text{citric acid}}{192.124\,g\text{ citric acid}}$
$=5\times10^{-3}\,mol\text{ citric acid}$
