Answer
$17.4 \ \mu \ mol$
Work Step by Step
For these problems, find the molar mass of the given compound. Then, convert to moles to solve.
$ \frac{.0034 g}{1}* \frac{1 mol}{195.8 g} = 17.4 \times 10^{-6}mol=17.4 \mu \ mol $
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