Answer
$2.23\times10^{23}\,Ag\,atoms$
Work Step by Step
Mass of silver= $43.2\,g\times\frac{92.5}{100}=39.96\,g$
Amount of silver=
$39.96\,g\,Ag\times\frac{1\,mol\,Ag}{107.8682\,g \,Ag}= 0.370452\,mol\,Ag$
Number of silver atoms=
$0.370452\,mol\,Ag\times\frac{6.022\times10^{23}\,Ag\,atoms}{1\,mol\,Ag}$
$=2.23\times10^{23}\,Ag\,atoms$
