Answer
See answer below.
Work Step by Step
Water as a base:
$HBr(aq)+H_2O(l)\leftrightarrow H_3O^+(aq)+Br^-(aq)$
Water as an acid:
$NH_3(aq)+H_2O(l)\leftrightarrow NH_4^+(aq)+OH^-(aq)$
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