Answer
$NiCl_{2}(aq) + (NH_{4})_{2}S(aq) → NiS(s) + 2(NH_{4})Cl(aq)$
Net ionic equation:
$Ni^{+2}(aq) + S^{-2}(aq) → NiS(s)$
Work Step by Step
$NiCl_{2}(aq) + (NH_{4})_{2}S(aq) → NiS(s) + 2(NH_{4})Cl(aq)$
Net ionic equation:
$Ni^{+2}(aq) + S^{-2}(aq) → NiS(s)$