Answer
$HClO_4(aq)+H_2O(l)\rightarrow H_3O^+(aq)+ClO_4^-(aq)$
Work Step by Step
Perchloric acid: $HClO_4$
$HClO_4(aq)+H_2O(l)\rightarrow H_3O^+(aq)+ClO_4^-(aq)$
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