Answer
See answer below.
Work Step by Step
Benzoic acid in water:
$C_6H_5CO_2H(aq)+H_2O(aq)\rightarrow H_3O^+(aq)+C_6H_5CO_2^-(aq)$
Benzoic acid: acid, proton donor
Water: base, proton acceptor
Hydronium: acid, proton donor
Benzoate ion: base, proton acceptor
It's a reactant-favored reaction because benzoic acid is a weak acid.