Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677c: 73

Answer

1.22 mol

Work Step by Step

$AgCl+2\ NH_3\leftrightarrow Ag(NH_3)_2^++Cl^-$ $K=Ksp\dot{}Kf=1.98\dot{}10^{-3}$ Full dissolution: $[Ag(NH_3)_2^+]=[Cl^-]=0.05\ M$ $1.98\dot{}10^{-3}=0.05^2/[NH_3]^2\rightarrow [NH_3]=1.12\ M$ Total NH3 added: $1.12\ M (NH_3)+ 2\dot{}0.05\ M (complex)=1.22\ M$ $n=1.22\ M\dot{}1.0\ L=1.22\ mol$
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