Answer
See the answer below.
Work Step by Step
Pure water:
$Ksp=[Ag^+][I^-]=s^2$
$s=\sqrt{8.5\dot{}10^{-17}}=9.22\dot{}10^{-9}\ M$
$s^*=9.22\dot{}10^{-9}\ mol/L\dot{}234.77\ g/mol=2.16\dot{}10^{-6}\ mg/mL$
With AgNO3:
$Ksp=s\dot{}(s+0.020)$
$s=4.25\dot{}10^{-15}\ M$
$s^*=4.25\dot{}10^{-15}\ mol/L\dot{}234.77\ g/mol=9.98\dot{}10^{-13}\ mg/mL$