Answer
Yes.
Work Step by Step
$[Mg^2+]=0.10\ M\times 75\ mL/(75+25)\ mL=0.075\ M$
$[OH^-]=0.010\ M\times 25\ mL/(75+25)\ mL=0.0025\ M$
$Qsp=[Mg^{2+}][OH^-]^2$
$Qsp=0.075\dot{}0.0025^2=6.25\dot{}10^{-6}>Ksp=5.6\dot{}10^{-12}$
Since Qsp is bigger than Ksp, precipitation will occur.