Answer
$-24.6^{\circ}C$
Work Step by Step
Molality: $(52.5\ g\div25.94\ g/mol)\div(306/1000)kg=6.614\ m$
Freezing point depression: $\Delta T_f=iK_fm=2\times-1.86^{\circ}C/m\times 6.614\ m=-24.60^{\circ}C$
Freezing point $-24.6^{\circ}C$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 13 Solutions and Their Behavior - Study Questions - Page 505b: 47
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
