Answer
$-0.36^{\circ}C$
Work Step by Step
Molality: $(15\ g\div 342.30\ g/mol)\div0.225\ kg=0.195\ m$
Freezing point depression: $\Delta T_f=K_fm=-1.86^{\circ}C/m\times0.195\ m=-0.36^{\circ}C$
Freezing point $-0.36^{\circ}C$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 13 Solutions and Their Behavior - Study Questions - Page 505b: 35
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