Answer
$2.5\ kg$
Work Step by Step
Freezing point depression: $-15.0°C$
Molality: $\Delta T_f=K_fm\rightarrow -15.0=-1.86m\rightarrow m=8.06\ m$
Mass of ethylene glycol: $8.06\ mol/kg\times 5.0\ kg\times 62.07\ g/mol=2502.82\ g$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 13 Solutions and Their Behavior - Study Questions - Page 505b: 34
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