Answer
See the answer below.
Work Step by Step
Boiling point elevation: $80.26-80.10=0.16^{\circ}C$
Molality: $\Delta T_b=K_bm\rightarrow 0.16^{\circ}C=2.53^{\circ} C/m\times m\rightarrow m=0.063\ m$
Number of moles: $m=n/m_{solvent}\rightarrow n=0.063\ m\times (11.12/1000)\ kg=7.03\times10^{-4}\ mol$
Molar mass: $0.255\ g\div 7.03\times10^{-4}\ mol=362.61\ g/mol$
Molar mass of empirical formula: $184.02\ g/mol$
Molar mass ratio: $362.61\div 184.02=1.97\approx 2$
Molecular formula: $2\times empirical\ formula=C_{20}H_{16}Fe_2$
