Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505b: 29

Answer

$84.15^{\circ}C$

Work Step by Step

Molality: $0.200\ mol\div 0.125\ kg=1.6\ m$ Boiling Point Elevation: $\Delta T_b=K_b\times m=2.53^{\circ}C/m\times1.6\ m=4.05\ ^{\circ}C$ Mixture boiling point: $80.10+4.05=84.15^{\circ}C$
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