Answer
The pH of a pure water solution at 37 $^{\circ}$ is 6.801.
Work Step by Step
1. Find $pK_w$:
$pK_w = -log(K_w) = -log(2.5 \times 10^{-14})$
$pK_w \approx 13.602$
2. Pure water = Neutral, therefore: $pH = pOH$
Create a unknown, called "x", where: x = pH = pOH.
Therefore, using the equation: pH + pOH = pKw
x + x = pKw
2x = 13.602
x = $\frac{13.602}{2}$ = 6.801
So, the pH (and the pOH) of a pure water solution at 37 $^{\circ}$ is 6.801.
