Answer
(a) pH = 0.0086
(b) pH = 1.45
(c) pH = 5.82
Work Step by Step
For strong acids: $[Acid] = [H_3O^+]$.
- $HI, HClO_4$ and $HCl$ are strong acids.
(a)
$pH = -log[H_3O^+]$
$pH = -log( 1.02)$
$pH = 0.0086$
(b)
$pH = -log[H_3O^+]$
$pH = -log( 3.5 \times 10^{- 2})$
$pH = 1.45$
(c)
$pH = -log[H_3O^+]$
$pH = -log( 1.5 \times 10^{- 6})$
$pH = 5.82$
