Answer
c) -89.2$^{\circ}$C, 183.9 K
Work Step by Step
Given F = -128.6^{\circ}F
Substitute this value in the equation,
C = $\frac{5}{9}$(-128.6-32)=-160.6x5/9=-89.2^{\circ}C
Then, we find C (temperature in $^{\circ}C$) = -89.2$^{\circ}$C
To get corresponding Kelvin scale value:
Use T K= t+ 273=-89.2+273=183.8K where t is the temperature in $^{\circ}$C , i.e. -89.2.
