Answer
This solution has $1.98 \times 10^{-3}$ moles, and its pOH is 0.443.
Work Step by Step
$n(moles) = C(M) * V(L)$
- 5.50ml = 0.0055L (ml to L - Divide by 1000)
$n(moles) = 0.360M * 0.0055L$
$n(moles) = 1.98 \times 10^{-3}$
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- Since KOH is a strong base:
$[KOH] = [OH^-] = 0.360M$
$pOH = -log[OH^-]$
$pOH = -log(0.360)$
$pOH = 0.443$
