Answer
(a) $[H_3O^+] = 2.05 \times 10^{- 11}M$
(b) $[H_3O^+] = 3.07 \times 10^{- 8}M$
(c) $[H_3O^+] = 5.95 \times 10^{- 11}M$
(d) $[H_3O^+] = 2.93 \times 10^{- 1}M$
Work Step by Step
(a)
$[OH^-] * [H^+] = Kw = 5.13 \times 10^{-13}$
$ 2.5 \times 10^{- 2} * [H^+] = 5.13 \times 10^{-13}$
$[H^+] = \frac{5.13 \times 10^{-13}}{ 2.5 \times 10^{- 2}}$
$[H^+] = 2.05 \times 10^{- 11}$
(b)
$[OH^-] * [H^+] = Kw = 5.13 \times 10^{-13}$
$ 1.67 \times 10^{- 5} * [H^+] = 5.13 \times 10^{-13}$
$[H^+] = \frac{5.13 \times 10^{-13}}{ 1.67 \times 10^{- 5}}$
$[H^+] = 3.07 \times 10^{- 8}$
(c)
$[OH^-] * [H^+] = Kw = 5.13 \times 10^{-13}$
$ 8.62 \times 10^{- 3} * [H^+] = 5.13 \times 10^{-13}$
$[H^+] = \frac{5.13 \times 10^{-13}}{ 8.62 \times 10^{- 3}}$
$[H^+] = 5.95 \times 10^{- 11}$
(d)
$[OH^-] * [H^+] = Kw = 5.13 \times 10^{-13}$
$ 1.75 \times 10^{- 12} * [H^+] = 5.13 \times 10^{-13}$
$[H^+] = \frac{5.13 \times 10^{-13}}{ 1.75 \times 10^{- 12}}$
$[H^+] = 2.93 \times 10^{- 1}$
