Answer
(a) $[H_3O^+] = 6.3 \times 10^{- 6}M$
(b) $[H_3O^+] = 1 \times 10^{- 16}M$
(c) $[H_3O^+] = 2.7 \times 10^{- 6}M$
Work Step by Step
(a)
$[H^+] = 10^{-pH}$
$[H^+] = 10^{- 5.2}$
$[H^+] = 6.3 \times 10^{- 6}$
(b)
$[H^+] = 10^{-pH}$
$[H^+] = 10^{- 16}$
$[H^+] = 1 \times 10^{- 16}$
(c)
$[OH^-] * [H^+] = Kw = 10^{-14}$
$ 3.7 \times 10^{- 9} * [H^+] = 10^{-14}$
$[H^+] = \frac{10^{-14}}{ 3.7 \times 10^{- 9}}$
$[H^+] = 2.7 \times 10^{- 6}$
