Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 7 - Quantum Theory and the Electronic Structure of Atoms - Questions & Problems - Page 318: 7.78

Answer

Please see the work below.

Work Step by Step

Boron The atomic number of B = 5 The correct electronic configuration of Boron = $1s^{2}2s^{2}2p^{1}$ One unpaired electron. Neon The atomic number of Neon = 10 The correct electronic configuration of Aluminum = $1s^{2}2s^{2}2p^{6}$ No unpaired electrons. Phosphorus The atomic number of P = 15 The correct electronic configuration of P = $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ or $[Ne] 3s^{2}3p^{3}$ Three unpaired electrons. Scandium The atomic number of Sc = 21 The correct electronic configuration of Sc = $[Ar]3d^{1}4s^{2}$ One unpaired electron. Manganese The atomic number of Mn = 25 The correct electronic configuration of Sc = $[Ar]3d^{5}4s^{2}$ Five unpaired electrons. Selenium The atomic number of Se = 34 The correct electronic configuration of Se = $[Ar]3d^{10}4s^{2}4p^{4}$ Two unpaired electrons. Krypton The atomic number of Kr = 36 The correct electronic configuration of Kr = $[Ar]3d^{10}4s^{2}4p^{6}$ No unpaired electrons. Iron The atomic number of Fe = 26 The correct electronic configuration of Fe = $[Ar]3d^{6}4s^{2}$ No unpaired electrons. Cadmium The atomic number of Cd = 48 The correct electronic configuration of Cd = $[Kr]4d^{10}5s^{2}$ No unpaired electrons. Iodine The atomic number of I = 53 The correct electronic configuration of I = $[Kr]4d^{10}5s^{2}5p^{5}$ One unpaired electron. Lead The atomic number of Pb = 82 The correct electronic configuration of I = $[Xe]4f^{14}5d^{10}6s^{2}6p^{2}$ Two unpaired electrons.
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