Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.2 Trigonometric Equations I - 6.2 Exercises - Page 267: 28

Answer

$\theta = 0^{\circ}, 180^{\circ}, 360^{\circ}$

Work Step by Step

$\cos^2 \theta = \sin^2 \theta + 1$ $\cos^2 \theta - \sin^2 \theta = 1$ $\cos 2\theta = 1$ $2\theta = 0^{\circ}, 360^{\circ}, 720^{\circ}$ $\theta = 0^{\circ}, 180^{\circ}, 360^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.