Answer
No solution.
Work Step by Step
$\sec^2 x + 2= -1$
$(\sec x)(\sec x) = -\frac{1}{2}$
$(\frac{1}{\cos x})(\frac{1}{\cos x}) = -\frac{1}{2}$
$(\frac{1}{\cos^2 x}) = -\frac{1}{2}$
$1 = -\frac{\cos^2 x}{2}$
$-2 = \cos^2 x$
No solution.
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