Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Learning the Mechanics - Page 242: 5.36c

Answer

$x=325.2$ $x=338.4$

Work Step by Step

According to table IV, page 773: $p(0\lt z\lt .84)=.3$ $p(z\lt.84)=p(z\leq0)+p(0\lt z\lt .84)=.5+.3=.80$ $z_0=\frac{x-\mu}{\sigma}$ $.84=\frac{x-300}{30}$ $x-300=25.2$ $x=325.2$ According to table IV, page 773: $p(0\lt z\lt 1.28)=.4$ $p(z\lt1.28)=p(z\leq0)+p(0\lt z\lt1.28)=.5+.4=.9$ $p(z\lt-1.28)=1-p(z\gt-1.28)=1-p(z\lt1.28)=1-.9=.10$ $z_0=\frac{x-\mu}{\sigma}$ $-1.28=\frac{x-300}{30}$ $x-300=38.4$ $x=338.4$
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