Answer
$p(6\leq x\leq10)=.3023$
Work Step by Step
$z=\frac{x-\mu}{\sigma}=\frac{10-11}{2}=-.5$
$z=\frac{x-\mu}{\sigma}=\frac{6-11}{2}=-2.5$
$p(6\leq x\leq10)=p(-2.5\leq z\leq-.5)=p(-2.5\leq z\leq0)-p(-.5\lt z\leq0)=p(0\lt z\leq2.5)-p(0\lt z\leq.5)=.4938-.1915=.3023$
According to Table IV, page 773:
$p(0\lt z\leq.5)=.1915$
$p(0\lt z\leq2.5)=.4938$