Answer
$p(76\leq x\leq 124)=.9974$
Work Step by Step
$z_0=\frac{x-\mu}{\sigma}=\frac{76-100}{8}=-3$
$z_0=\frac{x-\mu}{\sigma}=\frac{124-100}{8}=3$
According to table IV, page 773:
$p(0\lt z\lt 3)=.4987$
$p(76\leq x\leq 124)=p(-3\leq z\leq 3)=2p(0\leq z\leq3)=2(.4987)=.9974$