Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Applying the Concepts - Basic - Page 242: 5.40c

Answer

$p(x\lt1)=.3336$

Work Step by Step

$z_0=\frac{x-\mu}{\sigma}=\frac{1-5.26}{10}=-.43$ According to table IV, page 773: $p(0\lt z\lt .43)=.1664$ $p(x\lt1)=p( z\lt-.43)=p(z\lt0)-p(-.43\lt z\lt0)=.5-1.664=.3336$
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