Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Applying the Concepts - Basic - Page 242: 5.37c

Answer

$p(x\gt25)=.0122$

Work Step by Step

$z_0=\frac{x-\mu}{\sigma}=\frac{90-11}{4}=2.25$ According to table IV, page 773: $p(0\lt z\lt 2.25)=.4878$ $p(x\gt25)=p(z\gt2.25)=p(z\gt0)-p(0\lt z\lt 2.25)=.5-.4878=.0122$
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