Answer
It is hard to believe given that the probability of a 25-year-old woman being in the WPOWER50 is less than .1%
Work Step by Step
$z=\frac{x-\mu}{\sigma}=\frac{25-50}{6.4}=-3.91$
According to table IV, page 773:
$p(0\lt z\lt3.91)\gt.4990$
$p(x\leq25)=p(z\leq-3.91)=p(z\lt0)-p(-3.91\lt z\lt0)=.5-p(0\lt z\lt3.91)\lt.001$
