Answer
$p(55\lt x\lt60)=.1583$
Work Step by Step
$z=\frac{x-\mu}{\sigma}=\frac{55-50}{6.4}=.78$
$z=\frac{x-\mu}{\sigma}=\frac{60-50}{6.4}=1.56$
According to table IV, page 773:
$p(0\lt z\lt .78)=.2823$
$p(0\lt z\lt1.56)=.4406$
$p(55\lt x\lt60)=p(.78\lt z\lt1.56)=p(0\lt z\lt 1.56)-p(0\lt z\lt .78)=.4406-.2823=.1583$