Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Applying the Concepts - Basic - Page 242: 5.39a

Answer

$p(55\lt x\lt60)=.1583$

Work Step by Step

$z=\frac{x-\mu}{\sigma}=\frac{55-50}{6.4}=.78$ $z=\frac{x-\mu}{\sigma}=\frac{60-50}{6.4}=1.56$ According to table IV, page 773: $p(0\lt z\lt .78)=.2823$ $p(0\lt z\lt1.56)=.4406$ $p(55\lt x\lt60)=p(.78\lt z\lt1.56)=p(0\lt z\lt 1.56)-p(0\lt z\lt .78)=.4406-.2823=.1583$
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