Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Applying the Concepts - Basic - Page 242: 5.38b

$p(100\lt x\lt110)=.4678$

$z_0=\frac{x-\mu}{\sigma}=\frac{100-105.3}{8.0}=-.66$ $z_0=\frac{x-\mu}{\sigma}=\frac{110-105.3}{8.0}=.59$ According to table IV, page 773: $p(0\lt z\lt .59)=.2224$ $p(0\lt z\lt .66)=.2454$ $p(100\lt x\lt110)=p(-.66\lt z\lt.59)=p(-.66\lt z\lt0)+p(0\lt z\lt.59)=p(0\lt z\lt .66)+p(0\lt z\lt.59)=.2454+.2224=.4678$