Answer
$-4i-2j + 2k$
Work Step by Step
Suppose that the two vectors can be represented as: $v=v_1i+v_2j+v_3k$ and $w=w_1i+w_2j+w_3k$, then their cross product of such vectors can be obtained in the form of determinate as :
$ v \times w=\begin{vmatrix} i & j & k \\ v_1 & v_2 & v_3 \\ w_1 & w_2 & w_3 \\ \end{vmatrix}=(v_2w_3-v_3w_2)i-(v_1w_3-v_3w_1)j+(v_1w_2-v_2w_1)k$
A vector that will be orthogonal to two vectors let us say $u$ and $i+j$ is their cross -product.
Here,we have the cross product of two given vectors as :
$u \times (i+j) =\begin{vmatrix} i & j & k \\ 2 & -3 & 1 \\ 0 & 1 & 1 \\ \end{vmatrix}\\=[(-3)(1) -(1)(1)] i -j [(2)(1)-(1)(0)]+k [(2)(1) -(-3)(0)] \\=-4i-2j + 2k$
