Answer
$-18i -14j -6k$
Work Step by Step
Let us consider two vectors $v=xi+yj+zk$ and $w=pi+qj+rk$. Then the cross product of the two vectors $v$ and $w$ can be computed in the form of the determinant as:
$ v \times w=\begin{vmatrix}
i & j & k \\
x & y & z \\
p & q & r \\ \end{vmatrix}$
We have:
$det =v \times u =[(-3)(4)-(1)(6)] i -j [(2)(4) - (1)(-6)]+k [(2)(6) -(-3) (-6)]=-18i -14j -6k$
