Answer
$-27i-21j-9k$
Work Step by Step
Let us consider two vectors $v=xi+yj+zk$ and $w=pi+qj+rk$. Then the cross product of the two vectors $v$ and $w$ can be computed in the form of the determinant as:
$ v \times w=\begin{vmatrix}
i & j & k \\
x & y & z \\
p & q & r \\ \end{vmatrix}$
We have:
$det =3u \times v =[(-9)(2)-(3)(3)] i -j [(6)(2) - (3)(-3)]+k [(6)(3) -(-9) (-3)]=-27i-21j-9k$
