Answer
See below.
Work Step by Step
Use the Sum-to-Product Formula, we have:
$LHS=\frac{sin(4\theta)-sin(8\theta)}{cos(4\theta)-cos(8\theta)}=\frac{2cos(\frac{4\theta+8\theta}{2})sin(\frac{4\theta-8\theta}{2})}{-2sin(\frac{4\theta+8\theta}{2})sin(\frac{4\theta-8\theta}{2})}
=-\frac{cos(6\theta)}{sin(6\theta)}=-cot(6\theta)=RHS$