Answer
$ \frac{1}{2}(\frac{\sqrt 3}{2}-1) $
Work Step by Step
Use the Product-to-Sum formula, we have:
$sin195^\circ\cdot cos75^\circ=\frac{1}{2}[sin(195^\circ+75^\circ)+sin(195^\circ-75^\circ)]=\frac{1}{2}[sin(270^\circ)+sin(120^\circ)]=\frac{1}{2}[-1+\frac{\sqrt 3}{2}] =\frac{1}{2}(\frac{\sqrt 3}{2}-1) $