Answer
$-\frac{1}{2}$.
Work Step by Step
Given point $(6,-3)$ in quadrant IV, we have $x=6, y=-3$, thus $tan\theta=\frac{y}{x}=-\frac{1}{2}$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Chapter Test - Page 460: 24
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